Bell Work
Work through Kepler's 3 Laws. 1: Orbital paths are elliptical and have foci 2: A satellite passing similar times will sweep over the same area. 3. All satellites in the same system will have the same Kepler's Constant. Lesson 1. Discussion about the History of planetary Motion
4. Answer the 8 questions from this link in your notebook: 
Homework
Notes

Practice Problem #1A satellite wishes to orbit the earth at a height of 100,000 Meters (approximately 60 miles) above the surface of the earth. Determine the speed, acceleration and orbital period of the satellite. (Given: M earth = 5.98 x 10^24 kg, Rearth = 6.37 x 10^6 m)
Practice Problem #2
The period of the moon is approximately 27.2 days (2.35 x 10^6s). Determine the radius of the moon's orbit and the orbital speed of the moon. (Given: Mearth = 5.98 x 10^24 kg, Rearth = 6.37 x 10^6 m)
Practice Problem #3
A geosynchronous satellite is a satellite that orbits the earth with an orbital period of 24 hours, thus matching the period of the earth's rotational motion. A special class of geosynchronous satellites is a geostationary satellite. A geostationary satellite orbits the earth in 24 hours along an orbital path that is parallel to an imaginary plane drawn through the Earth's equator. Such a satellite appears permanently fixed above the same location on the Earth. If a geostationary satellite wishes to orbit the earth in 24 hours (86400 s), then how high above the earth's surface must it be located? (Given: Mearth = 5.98x10^24 kg, Rearth= 6.37 x 10^6 m)
Practice Problem #2
The period of the moon is approximately 27.2 days (2.35 x 10^6s). Determine the radius of the moon's orbit and the orbital speed of the moon. (Given: Mearth = 5.98 x 10^24 kg, Rearth = 6.37 x 10^6 m)
Practice Problem #3
A geosynchronous satellite is a satellite that orbits the earth with an orbital period of 24 hours, thus matching the period of the earth's rotational motion. A special class of geosynchronous satellites is a geostationary satellite. A geostationary satellite orbits the earth in 24 hours along an orbital path that is parallel to an imaginary plane drawn through the Earth's equator. Such a satellite appears permanently fixed above the same location on the Earth. If a geostationary satellite wishes to orbit the earth in 24 hours (86400 s), then how high above the earth's surface must it be located? (Given: Mearth = 5.98x10^24 kg, Rearth= 6.37 x 10^6 m)